3.5.29 \(\int \frac {(a^2+2 a b x^2+b^2 x^4)^2}{x^2} \, dx\) [429]

Optimal. Leaf size=48 \[ -\frac {a^4}{x}+4 a^3 b x+2 a^2 b^2 x^3+\frac {4}{5} a b^3 x^5+\frac {b^4 x^7}{7} \]

[Out]

-a^4/x+4*a^3*b*x+2*a^2*b^2*x^3+4/5*a*b^3*x^5+1/7*b^4*x^7

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Rubi [A]
time = 0.02, antiderivative size = 48, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {28, 276} \begin {gather*} -\frac {a^4}{x}+4 a^3 b x+2 a^2 b^2 x^3+\frac {4}{5} a b^3 x^5+\frac {b^4 x^7}{7} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a^2 + 2*a*b*x^2 + b^2*x^4)^2/x^2,x]

[Out]

-(a^4/x) + 4*a^3*b*x + 2*a^2*b^2*x^3 + (4*a*b^3*x^5)/5 + (b^4*x^7)/7

Rule 28

Int[(u_.)*((a_) + (c_.)*(x_)^(n2_.) + (b_.)*(x_)^(n_))^(p_.), x_Symbol] :> Dist[1/c^p, Int[u*(b/2 + c*x^n)^(2*
p), x], x] /; FreeQ[{a, b, c, n}, x] && EqQ[n2, 2*n] && EqQ[b^2 - 4*a*c, 0] && IntegerQ[p]

Rule 276

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*(a + b*x^n)^p,
 x], x] /; FreeQ[{a, b, c, m, n}, x] && IGtQ[p, 0]

Rubi steps

\begin {align*} \int \frac {\left (a^2+2 a b x^2+b^2 x^4\right )^2}{x^2} \, dx &=\frac {\int \frac {\left (a b+b^2 x^2\right )^4}{x^2} \, dx}{b^4}\\ &=\frac {\int \left (4 a^3 b^5+\frac {a^4 b^4}{x^2}+6 a^2 b^6 x^2+4 a b^7 x^4+b^8 x^6\right ) \, dx}{b^4}\\ &=-\frac {a^4}{x}+4 a^3 b x+2 a^2 b^2 x^3+\frac {4}{5} a b^3 x^5+\frac {b^4 x^7}{7}\\ \end {align*}

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Mathematica [A]
time = 0.01, size = 48, normalized size = 1.00 \begin {gather*} -\frac {a^4}{x}+4 a^3 b x+2 a^2 b^2 x^3+\frac {4}{5} a b^3 x^5+\frac {b^4 x^7}{7} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a^2 + 2*a*b*x^2 + b^2*x^4)^2/x^2,x]

[Out]

-(a^4/x) + 4*a^3*b*x + 2*a^2*b^2*x^3 + (4*a*b^3*x^5)/5 + (b^4*x^7)/7

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Maple [A]
time = 0.04, size = 45, normalized size = 0.94

method result size
default \(-\frac {a^{4}}{x}+4 a^{3} b x +2 a^{2} b^{2} x^{3}+\frac {4 a \,b^{3} x^{5}}{5}+\frac {b^{4} x^{7}}{7}\) \(45\)
risch \(-\frac {a^{4}}{x}+4 a^{3} b x +2 a^{2} b^{2} x^{3}+\frac {4 a \,b^{3} x^{5}}{5}+\frac {b^{4} x^{7}}{7}\) \(45\)
norman \(\frac {\frac {1}{7} b^{4} x^{8}+\frac {4}{5} a \,b^{3} x^{6}+2 a^{2} b^{2} x^{4}+4 a^{3} b \,x^{2}-a^{4}}{x}\) \(48\)
gosper \(-\frac {-5 b^{4} x^{8}-28 a \,b^{3} x^{6}-70 a^{2} b^{2} x^{4}-140 a^{3} b \,x^{2}+35 a^{4}}{35 x}\) \(49\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b^2*x^4+2*a*b*x^2+a^2)^2/x^2,x,method=_RETURNVERBOSE)

[Out]

-a^4/x+4*a^3*b*x+2*a^2*b^2*x^3+4/5*a*b^3*x^5+1/7*b^4*x^7

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Maxima [A]
time = 0.29, size = 44, normalized size = 0.92 \begin {gather*} \frac {1}{7} \, b^{4} x^{7} + \frac {4}{5} \, a b^{3} x^{5} + 2 \, a^{2} b^{2} x^{3} + 4 \, a^{3} b x - \frac {a^{4}}{x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b^2*x^4+2*a*b*x^2+a^2)^2/x^2,x, algorithm="maxima")

[Out]

1/7*b^4*x^7 + 4/5*a*b^3*x^5 + 2*a^2*b^2*x^3 + 4*a^3*b*x - a^4/x

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Fricas [A]
time = 0.35, size = 48, normalized size = 1.00 \begin {gather*} \frac {5 \, b^{4} x^{8} + 28 \, a b^{3} x^{6} + 70 \, a^{2} b^{2} x^{4} + 140 \, a^{3} b x^{2} - 35 \, a^{4}}{35 \, x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b^2*x^4+2*a*b*x^2+a^2)^2/x^2,x, algorithm="fricas")

[Out]

1/35*(5*b^4*x^8 + 28*a*b^3*x^6 + 70*a^2*b^2*x^4 + 140*a^3*b*x^2 - 35*a^4)/x

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Sympy [A]
time = 0.03, size = 44, normalized size = 0.92 \begin {gather*} - \frac {a^{4}}{x} + 4 a^{3} b x + 2 a^{2} b^{2} x^{3} + \frac {4 a b^{3} x^{5}}{5} + \frac {b^{4} x^{7}}{7} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b**2*x**4+2*a*b*x**2+a**2)**2/x**2,x)

[Out]

-a**4/x + 4*a**3*b*x + 2*a**2*b**2*x**3 + 4*a*b**3*x**5/5 + b**4*x**7/7

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Giac [A]
time = 7.39, size = 44, normalized size = 0.92 \begin {gather*} \frac {1}{7} \, b^{4} x^{7} + \frac {4}{5} \, a b^{3} x^{5} + 2 \, a^{2} b^{2} x^{3} + 4 \, a^{3} b x - \frac {a^{4}}{x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b^2*x^4+2*a*b*x^2+a^2)^2/x^2,x, algorithm="giac")

[Out]

1/7*b^4*x^7 + 4/5*a*b^3*x^5 + 2*a^2*b^2*x^3 + 4*a^3*b*x - a^4/x

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Mupad [B]
time = 0.02, size = 44, normalized size = 0.92 \begin {gather*} \frac {b^4\,x^7}{7}-\frac {a^4}{x}+\frac {4\,a\,b^3\,x^5}{5}+2\,a^2\,b^2\,x^3+4\,a^3\,b\,x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a^2 + b^2*x^4 + 2*a*b*x^2)^2/x^2,x)

[Out]

(b^4*x^7)/7 - a^4/x + (4*a*b^3*x^5)/5 + 2*a^2*b^2*x^3 + 4*a^3*b*x

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